<?php
//tri polja u bazi "anketa" Prvo je "id", drugi je "glas", trece je "ip"//
$glas = $_POST['vote'];
$ip = getenv ('REMOTE_ADDR');
include "spajanje.php";
$sql_query = mysql_query("INSERT INTO glasanje(id, glas, ip) VALUES ('', '$glas', '$ip')") or die (mysql_error());
include ("anketa.htm");
echo "Uspjesno ste glasali <br>";
$sql = 'SELECT COUNT * glasanje where glas = "1"';
$result = mysql_query($sql)
or die (mysql_error());
?>
Kaze mi sljedece:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where glas = "1"' at line 1
--> Pa ako moze mala pomoc...vrtim sve na localhostu, MySQL - 5.0.24a-community-nt...
LP i hvala unaprijed